Скачать: CL | DM;

TTreeView&Table   Найти похожие ветки 

← →
Demon[DZ]   (2002-02-07 11:16) [0]

Privet vsem!
Moj vopros mozhet pokazatsja lamerskim:)
No vsjozhe, kak svjazat" tablicu "N_Group" s komponentom TTreeView?
Tablica N_Group sostoit:
ID ParentID Name

V pole "ParentID" hranitsja :
"null"- esli eta zapis" javljaetsja nazvaniem gruppi;
ljuboe zna4enie - esli eta zapis" javljaetsja podgruppoj;
Eto znachenie ravno znacheniju "ID" gruppi;

ID ParentID Name
1 null Group1 -Group1
2 null Group2 +Group2
3 1 SubGroup1 +SubGroup1
4 3 SubGroup2 -SubGroup2
5 3 SubGroup3 -SubGroup3

Pomogite kto mozhet, ili gde hotjabi dostat" horoshuju infu s primerami.
Zaranee Blagodaren!

---

← →
Demon[DZ]   (2002-02-07 11:20) [1]

oj nebol"shaja ope4atka:)

ID ParentID Name
1 null Group1 -Group1
2 null Group2 +Group2
3 2 SubGroup1 +SubGroup1
4 3 SubGroup2 -SubGroup2
5 3 SubGroup3 -SubGroup3

---

← →
Demon[DZ]   (2002-02-07 12:34) [2]

Vidimo dejstvitel"no lamerskij vopros, 4to nokto neho4et mne pomoch:(
Ladno budu dal"she s etim komponentom tr........sja

---

← →
yaJohn ©   (2002-02-07 13:11) [3]

procedure TForm1.Button1Click(Sender: TObject);
var i: integer;
Node: TTreeNode;
begin
TreeView1.Items.Clear;
Query1.First;
while not Query1.Eof do
begin
Node:=nil;
for i:=0 to TreeView1.Items.Count-1 do //takoy poisk krayne neefektiven :( Nujno svoy dumat"
if TreeView1.Items[i].Data=pointer(Query1.FieldByName("ParentID").asInteger)
then Node:=TreeView1.Items[i];
TreeView1.Items.AddChildFirst(Node,Query1.FieldByName("NAME").asString).Data:=pointer(Query1.FieldByName("ID").asInteger);
Query1.Next;
end;
end;
Kak eskiz...

---

← →
Demon[DZ]   (2002-02-07 13:56) [4]

yaJohn Spasibooooooooooo!
Rabotaet, Thanks!:)

---

Страницы: 1 вся ветка

Скачать: CL | DM;



Память: 0.45 MB
Время: 0.007 c