Как сконвертить строку в base64?

← →
serg128 (2006-05-28 11:16) [0]

Как сконвертить строку в base64, но желательно без использования заумных бибилиотек? Приведите код, плиз! :)

Заранее спасибо!

← →
_n0p (2006-05-28 13:58) [1]

http://www.fourmilab.ch/webtools/base64/rfc1341.html
http://www.fourmilab.ch/webtools/base64/
http://www.google.ru/search?sourceid=navclient-ff&ie=UTF-8&rls=GGGL,GGGL:2005-09,GGGL:ru&q=base64

← →
atruhin © (2006-05-28 14:33) [2]

Function EncodeBase64( Data: PChar; Len: Integer ): String;
const B64 : array [0..63] of Char = "ABCDEFGHIJKLMNOPQRSTUVWXYZ" +
"abcdefghijklmnopqrstuvwxyz" +
"0123456789+/";
var Ic : Integer;
Pi, Po: TPAByte;
C1 : DWord;
Begin
if Len > 0 then
Begin
SetLength( Result, ( ( Len + 2 ) div 3 ) * 4 );
Pi := Pointer( Data );
Po := Pointer( Result );
for Ic := 1 to Len div 3 do
Begin
C1 := Pi^[0] shl 16 + Pi^[1] shl 8 + Pi^[2];
Po^[0] := Byte( B64[( C1 shr 18 ) and $3f] );
Po^[1] := Byte( B64[( C1 shr 12 ) and $3f] );
Po^[2] := Byte( B64[( C1 shr 6 ) and $3f] );
Po^[3] := Byte( b64[( c1 ) and $3f] );
Inc( DWord( Po ), 4 );
Inc( DWord( Pi ), 3 );
end;
Case Len mod 3 of
1: Begin
C1 := Pi^[0] shl 16;
Po^[0] := Byte( B64[( C1 shr 18 ) and $3f] );
Po^[1] := Byte( B64[( C1 shr 12 ) and $3f] );
Po^[2] := Byte( "=" );
Po^[3] := Byte("=");
end;
2: Begin
C1 := Pi^[0] shl 16 + Pi^[1] shl 8;
Po^[0] := Byte( B64[( C1 shr 18 ) and $3f] );
Po^[1] := Byte( B64[( C1 shr 12 ) and $3f] );
Po^[2] := Byte( B64[( C1 shr 6 ) and $3f] );
Po^[3] := Byte("=");
end;
end;
end else Result := "";
end;

← →
atruhin © (2006-05-28 14:33) [3]

Function DecodeBase64( Data: PChar; Len: Integer ): String;
var I1, I2: Integer;
Pi, Po: TPAByte;
ch1 : Char;
c1 : DWord;
Begin
if ( Len > 0 ) and ( Len mod 4 = 0 ) then
Begin
Len := Len shr 2;
SetLength( Result, Len * 3 );
Pi := Pointer( Data );
Po := Pointer( Result );
for I1 := 1 to Len do
Begin
C1 := 0;
I2 := 0;
While True do
Begin
Ch1 := Char( Pi^[I2] );
Case Ch1 of
"A".."Z": C1 := C1 or ( DWord( Ch1 ) - Byte( "A" ) );
"a".."z": C1 := C1 or ( DWord( Ch1 ) - Byte( "a" ) + 26 );
"0".."9": C1 := C1 or ( DWord( Ch1 ) - Byte( "0" ) + 52 );
"+" : C1 := C1 or 62;
"/" : C1 := C1 or 63;
else
Begin
if I2 = 3 then
Begin
Po^[0] := C1 shr 16;
Po^[1] := Byte( C1 shr 8 );
SetLength( Result, Length( Result ) - 1 );
end else
Begin
Po^[0] := C1 shr 10;
SetLength( Result, Length( Result ) - 2 );
end;
Exit;
end;
end;
if I2 = 3 then break;
Inc( I2 );
C1 := C1 shl 6;
end;
Po^[0] := C1 shr 16;
Po^[1] := Byte( C1 shr 8 );
Po^[2] := Byte( C1 );
Inc( DWord( Pi ), 4 );
Inc( DWord( Po ), 3 );
end;
end else Result := "";
end;

← →
Жуков Олег (2006-05-28 19:49) [4]

> Как сконвертить строку в base64, но желательно без использования
> заумных бибилиотек? Приведите код, плиз! :)

не знаю, есть ли в D6, а в D7 и выше есть EncdDecd.pas
uses EncdDecd;
функции EncodeString, DecodeString, EncodeStream, DecodeStream;

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